64x^2+23x-21=0

Solution for 64x^2+23x-21=0 equation:

64x^2+23x-21=0

a = 64; b = 23; c = -21;
Δ = b2-4ac
Δ = 232-4·64·(-21)
Δ = 5905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{5905}}{2*64}=\frac{-23-\sqrt{5905}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{5905}}{2*64}=\frac{-23+\sqrt{5905}}{128}
$